简单的编程代码让你轻松入门 Python (简单的编程代码大全)

题目：

输入两个数字，比较大小，然后按照大小输出。

代码：

def cmpNum():
  a = input("请输入一个数字：")
  b = input("请输入一个数字：")
  if a >= b:
    print(a, b)
  else:
    print(b, a)

cmpNum()
  

结果：

• 请输入一个数字：159 请输入一个数字：159 结果一：
• 请输入一个数字：9568 请输入一个数字：1452 结果二：

题目：

有一道Python编程题，求代码：

a = [] for i in [w, c, li]: for j in [z, y, liu]: if i==w and j==z: print("notmatch", i, j) elif i==li and j==z or i==li and j==liu: print("notmatch", i, j) elif i==li and j==y: print("match", i, j, ((i, j))) elif i==w and j==liu: print("match", i, j, ((i, j))) elif i==c and j==z: print("match", i, j, ((i, j))) print(a)

输出：

>>>================================RESTART================================>>>
notFalse

     是否跟蛇碰上了
    if pos == head and pos == snakes[0]:
      is_coll = True

     蛇身子
    for snake in snakes:
      if pos == snake and pos == snakes[0]:
        is_coll = True
        break

    if not is_coll:
      break
  return pos

 定义坐标
food = gen_food()
food_color = (255, 255, 0)
direct = LEFT   left, right, up, down

 定义矩形
def rect(point, color):
  cell_width = W/COL
  cell_height = H/ROW
  left = point.col  cell_width
  top = point.row  cell_height
  pygame.draw.rect(window, color, (left, top, cell_width, cell_height))

 游戏循环
while quit:
   处理事件
  for event in pygame.event.get():
    if event.type == QUIT:
      quit = False
    elif event.type == KEYDOWN:
      if event.key == K_LEFT or event.key == K_a:
        direct = LEFT
      elif event.key == K_RIGHT or event.key == K_d:
        direct = RIGHT
      elif event.key == K_UP or event.key == K_w:
        direct = UP
      elif event.key == K_DOWN or event.key == K_s:
        direct = DOWN

   更新游戏状态
   ...

   绘制画面
  window.fill(bg_color)
  rect(head, head_color)
  for snake in snakes:
    rect(snake, snake_color)
  rect(food, food_color)

   更新显示
  pygame.display.update()
  

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